Kaya the Inexorable (Kaldheim #218)

Kaya l'Inesorabile {3}{W}{B}

Planeswalker Leggendario — Kaya

+1: Scegli fino a una creatura non pedina bersaglio. Metti un segnalino forma spettrale su di essa. Ha “Quando questa creatura muore o viene messa in esilio, falla tornare in mano al suo proprietario e crea una pedina creatura Spirito 1/1 bianca con volare”.

-3: Esilia un permanente non terra bersaglio.

−7: Ottieni un emblema con “All'inizio del tuo mantenimento, puoi lanciare una magia leggendaria dalla tua mano, dal tuo cimitero o scelta fra le carte che possiedi in esilio senza pagare il suo costo di mana”.

Loyalty: 5

Illustrated by Tyler Jacobson

Standard
Alchemy
Pioneer
Explorer
Modern
Historic
Legacy
Brawl
Vintage
Timeless
Commander
Pauper
Oathbreaker
Penny
Notes and Rules Information for Kaya l'Inesorabile:
  • Only the English version of a Magic card receives Oracle updates and errata. View this card in English. (Scryfall note)
  • The ghostform counter added by the first ability doesn’t have any functional importance. It’s there to remind you of the ability the creature gains. Even if that counter is removed from the creature, the triggered ability it gains will still work. (2021-02-05)
  • If a nontoken creature gains more than one instance of that triggered ability, each of them will trigger separately. You can return the card to its owner’s hand only once, but you’ll create a Spirit creature token for each of those abilities. (2021-02-05)
  • If you own a face-down card in exile, Kaya’s emblem will let you cast it only if you can look at the card (and only if it’s legendary). If you aren’t allowed to look at the card, you can’t cast it, even if you know it’s legendary. (2021-02-05)
  • If you cast a spell “without paying its mana cost,” you can’t choose to cast it for any alternative costs. You can, however, pay additional costs, such as kicker costs. If the card has any mandatory additional costs, those must be paid to cast the spell. (2021-02-05)
  • If the spell has {X} in its mana cost, you must choose 0 as the value of X. (2021-02-05)